A spring has a spring constant of 100 N/m. When the spring is compressed by 5 mm (such that \Delta xΔx is negative), determine the restoring spring force.

Given that spring constant, k = 100 N/m and displacement, x = - 5mm = - 0.005 m
The formula of restoring force according to Hooke's law,
[tex]F=-kx[/tex]Substituting the values, we get
[tex]\begin{gathered} F=-100(-0.005) \\ =\text{ 0.5 N} \end{gathered}[/tex]Thus, the force is 0.5 N