How many grams of carbon dioxide are produced when 191 g of methane (CH4) are burned completely as shown in the reaction below:

Answer
We have the following chemical reaction:
[tex]CH_4+2O_2\rightarrow CO_2+2H_2O[/tex]Now we calculate how many moles (n) of CH4 react, we use its molar mass:
[tex]M_{CH_4}=M_C+4.M_H=12\frac{g}{mol}+41.\frac{g}{mol}=16\frac{g}{mol}[/tex][tex]n=\frac{191g}{16\frac{g}{mol}}=11.93mol[/tex]Now we calculate the moles of CO2 produced. As we can see from the equation for every mol of CH4 that reacts 1 mol of CO2 is produced. So in this case 11.93 moles are produced. Now we calculate the corrisponding mass.
[tex]m_{CO_2}=11.93mol.44\frac{g}{mol}=524g[/tex]So the answer is 524g.