Given:
[tex]\begin{bmatrix}{1} & {2} & {3|} & {6} \\ {1} & {1} & {1|} & {-2} \\ {0} & {2} & {1|} & {5} \\ {} & {} & {} & {}\end{bmatrix}[/tex]
Required:
[tex]\text{We need to use the given operation }-R_1+R_2\rightarrow R_2.[/tex]
Explanation:
[tex]\text{We know that }R_1\text{ represents the first row and }R_2\text{ represents the second row.}[/tex]
[tex]-R_1+R_2\rightarrow R_2\text{ means the second row of the matrix can be found by subtracting first row from second row.}[/tex]
[tex]\begin{bmatrix}{1} & {2} & {3|} & {6} \\ {1-1} & {1-2} & {1-3|} & {-2-6} \\ {0} & {2} & {1|} & {5} \\ {} & {} & {} & {}\end{bmatrix}[/tex]
[tex]\begin{bmatrix}{1} & {2} & {3|} & {6} \\ {0} & {-1} & {-2|} & {-8} \\ {0} & {2} & {1|} & {5} \\ {} & {} & {} & {}\end{bmatrix}[/tex]
Final answer:
[tex]\begin{bmatrix}{1} & {2} & {3|} & {6} \\ {0} & {-1} & {-2|} & {-8} \\ {0} & {2} & {1|} & {5} \\ {} & {} & {} & {}\end{bmatrix}[/tex]
