Rewrite the equation as:
[tex]x^2-7x+13=0[/tex]use the quadratic formula:
[tex]\begin{gathered} ax^2+bx+c=0 \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \end{gathered}[/tex]so:
[tex]\begin{gathered} x=\frac{-(-7)\pm\sqrt[]{(-7)^2-4(1)(13)}}{2(1)} \\ x=\frac{-7\pm\sqrt[]{49-52}}{2} \\ x=\frac{-7\pm\sqrt[]{-3}}{2} \\ x=\frac{1}{2}(7\pm\sqrt[]{3}i) \end{gathered}[/tex]