Respuesta :
Answer
Hence, the partial pressure of gas 3 in atm = 0.3 atm
Explanation
Given:
Total pressure of the three gases, P(total) = 2.8 atm
Partial pressure of gas 1, P₁ = 480 mmHg
Partial pressure of gas 2, P₂ = 1450 torr
What to find:
The partial pressure of gas 3 in atm.
Step-by-step solution:
According to Dalton's law of partial pressure which states that the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures of the gases in the mixture. i.e
[tex]P_{total}=P_1+P_2+P_3+....P_n[/tex]Since the unit of the given partial pressures are not the same with the that of the total pressure, then you need to convert them to atm.
Conversion factor:
760 mmHg = 1 atm
760 torr = 1 atm
Therefore,
The partial pressure of gas 1, P₁ = 480 mmHg = (480 mmHg/760 mmHg) x 1 atm = 0.6 atm
The partial pressure of gas 2, P₂ = 1450 torr = (1450 torr/760 torr) x 1 atm = 1.9 atm
Putting P₁ = 0.6 atm, P₂ = 1.9 atm and P(total) = 2.8 atm into the partial pressure formula above to get the partial pressure of gas 3:
[tex]\begin{gathered} 2.8atm=0.6atm+1.9atm+P_3 \\ \\ 2.8atm=2.5atm+P_3 \\ \\ P_3=2.8atm-2.5atm \\ \\ P_3=0.3atm \end{gathered}[/tex]Hence, the partial pressure of gas 3 in atm = 0.3 atm
