Suppose a tunnel for a road is in the shape of a semi-ellipse represented by the equation x^2/400+y^2/144=1 with measurements given in feet. Engineers havedecided that the tunnel must be twice as wide and 1.5 times as tall Write the equation that represents the new tunnel

Suppose a tunnel for a road is in the shape of a semiellipse represented by the equation x2400y21441 with measurements given in feet Engineers havedecided that class=

Respuesta :

In this case the formula of an ellipse is

[tex]\frac{x^2}{a^2}+\frac{y^2}{b^2}=1[/tex]

In our case a helps to the wise and b with the tall

[tex]a=\sqrt[]{400}=20[/tex][tex]b=\sqrt[]{144}=12[/tex]

Then if we need twice the wide

[tex]2a=2(20)=40[/tex]

and 1.5 the tall

[tex]1.5(12)=18[/tex]

Therefore our new equation is

[tex]\frac{x^{2}}{1600}+\frac{y^{2}}{324}=1[/tex]

ANSWER

[tex]D\text{. }\frac{x^{2}}{1600}+\frac{y^{2}}{324}=1[/tex]