Find the perimeter of the equilateral triangle h = 6x + 8 b = 12x - 4
Perimeter = 3*L (equilateral triangle)
Pythagoras theorem
[tex]H^2=C1^2+C2^2[/tex][tex]L^2=H^2^{}+(L/2)^2[/tex][tex]L^2-\mleft(L/2\mright)^2=H^2[/tex]So we need to determine H
6x +8b = 12x - 4
12x-6x= 8b-
