Suppose a normal distribution has a mean of 89 and astandard deviation of 7.

The mean of 89
The standard deviation of 7
Solution[tex]Z=\frac{x-\mu}{\sigma}[/tex]Where
[tex]\begin{gathered} x=82 \\ \sigma=7 \\ \mu=89 \end{gathered}[/tex][tex]Z=\frac{82-89}{7}=-1[/tex]The final answerOption B[tex]0.16[/tex]