[tex]\begin{gathered} f(x)\text{ = x - 3 and g(x) = }\frac{8}{x},\text{ } \\ \text{Then, }\frac{g}{f}\text{ = }\frac{\frac{8}{x}}{x\text{ - 3}}\text{ = }\frac{8}{x(x\text{ - 3)}} \\ \text{Considering the denominator, we can't have x = 0 or x = 3. Because this will make the function undefined. } \\ \text{The domain is a union of intervals } \\ \text{-}\infty\text{ }\leq x<0 \\ 03 \end{gathered}[/tex]
In interval notation,
The domain is;
[tex]\begin{gathered} (-\infty,0) \\ (0,3) \\ (3,\infty) \end{gathered}[/tex]
