Explanation:
The question is given below as
[tex]\begin{gathered} f(x)=x^2+3 \\ find, \\ f(4y) \end{gathered}[/tex]
Concept:
Substitute the value of x with 4y in the function above, we will have
[tex]\begin{gathered} f(x)=x^{2}+3 \\ f(4y)=(4y)^2+3 \\ f(4y)=16y^2+3 \end{gathered}[/tex]
Hence,
The final answer is
[tex]\Rightarrow f(4y)=16y^2+3[/tex]
