Solution
Given
[tex]\begin{gathered} 4x+8y=16 \\ at\text{ }x-intercept,y=0 \\ 4x+8(0)=16 \\ 4x=16 \\ x=\frac{16}{4} \\ x=4 \end{gathered}[/tex]To find y - intercept as shown below
[tex]\begin{gathered} 4x+8y=16 \\ at\text{ }y-intercept,x=0 \\ 4(0)+8y=16 \\ 8y=16 \\ y=\frac{16}{8} \\ y=2 \end{gathered}[/tex]We can also write the intercepts in co-ordinate form as shown below
For x-intercept : ( 4,0 )
For y -intercept ; ( 0, 2 )
Let us show the graph of the line below
