Given,
[tex]-3x^2+2x+4=-x-3[/tex][tex]-3x^2+3x+7=0[/tex]Solving the above equation,
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]Here, a=-3, b=3 and c=7
Therefore,
[tex]x=\frac{-3\pm\sqrt[]{9+84}}{-6}[/tex][tex]x=\frac{-3+\sqrt[]{93}}{-6}\text{ or }x=\frac{-3-\sqrt[]{93}}{-6}\text{ }[/tex]Therefore,
[tex]x=-1.11\text{ or }x=2.11[/tex]