We are given the following equation:
[tex]4-3(x+2)=0[/tex]
We are asked to solve for "x". To do that we will subtract 4 from both sides:
[tex]\begin{gathered} 4-4-3(x+2)=-4 \\ -3(x+2)=-4 \end{gathered}[/tex]
Now we will divide both sides by -3:
[tex]\begin{gathered} \frac{-3(x+2)}{-3}=-\frac{4}{-3} \\ \\ x+2=\frac{4}{3} \end{gathered}[/tex]
Now we will subtract 2 from both sides:
[tex]\begin{gathered} x+2-2=\frac{4}{3}-2 \\ x=-\frac{2}{3} \end{gathered}[/tex]
Therefore, the value of "x" is -2/3.
