Using diffraction grating equation:
[tex]dsin(\theta)=n\lambda[/tex]Where:
[tex]\begin{gathered} d=Distance \\ \theta=Angle=3.52 \\ \lambda=Wavelength=2.58\times10^7 \\ n=integer_{\text{ }}number_{\text{ }}to_{\text{ }}next_{\text{ }}bright_{\text{ }}fringe=3 \end{gathered}[/tex]Solve for d:
[tex]\begin{gathered} d=\frac{\lambda n}{sin(\theta)} \\ d=\frac{(3)(2.58\times10^7)}{sin(3.52)} \\ d\approx1.26\times10^5m \end{gathered}[/tex]