If 2 1n x + 1n 5 = 1n 80, then what is the value of x?

Answer: A
Given:
[tex]2\ln x+\ln 5=\ln 80[/tex]*subtract ln 5 from both sides:
[tex]2\ln x=\ln 80-\ln 5[/tex]*Divide both sides by 2
[tex]\ln x=\frac{\ln 80-\ln 5}{2}[/tex][tex]\ln x=\frac{\ln (\frac{80}{5})}{2}[/tex][tex]\ln x=\frac{\ln (16)}{2}=\frac{\ln (2^4)}{2}[/tex][tex]\ln x=\frac{4\ln (2)}{2}[/tex][tex]\ln x=2\ln (2)[/tex][tex]\ln x=\ln (2^2)[/tex][tex]\ln x=\ln (4)[/tex][tex]x=4[/tex]