How many moles of oxygen are needed to produce 9 moles of water in the combustion of ethane? Show your work in the space below.

Answer:
[tex]10.5\text{ moles}[/tex]Explanation:
Here, we want to get the number of moles of oxygen needed to produce 9 moles of water
From the balanced equation, 7 moles of oxygen gave 6 moles of water
x moles of oxygen will produce 9 moles of water
Mathematically therefore:
[tex]\begin{gathered} x\times6\text{ = 7}\times9 \\ 6x\text{ = 63} \\ x\text{ = }\frac{63}{6} \\ x\text{ = 10.5 moles} \end{gathered}[/tex]