Given:
The equation is,
[tex]4-3(x-3)=5(x+2)-8x[/tex]Simplify the equation,
[tex]\begin{gathered} 4-3\mleft(x-3\mright)=5\mleft(x+2\mright)-8x \\ \text{LHS}=4-3(x-3) \\ =4-3x-3\times(-3) \\ =4-3x+9 \\ =13-3x\ldots\ldots\text{.}\mathrm{}(1) \\ \text{RHS}=5(x+2)-8x \\ =5x+5(2)-8x \\ =-3x+10\ldots\ldots\ldots\ldots\text{.}(2) \end{gathered}[/tex]Now,
[tex]\begin{gathered} 13-3x=-3x+10 \\ -3x=-3x+10-13 \\ -3x=-3x-3 \\ \Rightarrow-3=0 \\ \Rightarrow No\text{ solution} \end{gathered}[/tex]