the equation x^2=9 has two solutions: 3 and -3. with that in mind, what is the other solution to the equation 17=0.018268·sup(sub(v,0),2)

Given,
The equation is,
[tex]17=0.018268v^2_o[/tex]Simplifying the equation,
[tex]\begin{gathered} 17=0.018268v^2_o \\ v^2_o=\frac{17}{0.018268} \\ v^2_o=930.589008 \\ v^{}_o=\sqrt{930.589008} \\ v^{}_o=30.505 \\ v^{}_o\approx31 \end{gathered}[/tex]Hence, the solution is 31 (approximately)