Given that the two resistors are connected in parallel and each resistance is 14 ohms.
The current in the circuit is I = 0.1 A.
We have to find the voltage of the battery.
Let the voltage be denoted by V.
First, we have to find the equivalent resistance.
[tex]\begin{gathered} \frac{1}{R_P}=\frac{1}{14}+\frac{1}{14} \\ =\frac{2}{14} \\ R_p=7\text{ ohm} \end{gathered}[/tex]The equivalent resistance is 7 ohm.
According to Ohm's law, the voltage can be calculated by the formula
[tex]\begin{gathered} V=R_pI \\ =7\times0.1 \\ =0.7\text{ V} \end{gathered}[/tex]Thus, the voltage of the battery is 0.7 V.
