Answer: m⁰
Given:
[tex]m^{-10}\cdot m^{10}[/tex]
According to the Product rule of exponents:
[tex]a^x\times a^y=a^{x+y}[/tex]
Applying this to the given expression and we will get:
[tex]\begin{gathered} m^{-10}\cdot m^{10} \\ =m^{-10+10}^{} \\ =m^0=1 \end{gathered}[/tex]
Since -10 + 10 equals 0, the answer in exponential form would be m⁰.
Note that any number raised to 0 is equal to 1.
