Given:
[tex](4-2i)(1+7i_{})[/tex]
To find: The product of the complex numbers
Explanation:
On multiplication we get,
[tex](4-2i)(1+7i_{})=4+28i-2i-14(i^2)[/tex]
We know that
[tex]i^2=-1[/tex]
Using the above identity, we get
[tex]\begin{gathered} =4+28i-2i-14(-1) \\ =4+26i+14 \\ =18+26i \end{gathered}[/tex]
Final answer: Option D
[tex]18+26i[/tex]
