We are dealing with a right triangle; therefore, we can use the trigonometric identity shown below
[tex]\begin{gathered} sin\theta=\frac{O}{H} \\ \theta\rightarrow\text{ inner angle of the triangle} \\ O\rightarrow\text{ opposite angle to }\theta \\ H\rightarrow\text{ hypotenuse} \end{gathered}[/tex]
Thus, in our case,
[tex]\begin{gathered} \Rightarrow sin(53\degree)=\frac{x}{15} \\ \Rightarrow x=15sin(53\degree) \\ \Rightarrow x=11.98 \\ \Rightarrow x\approx12 \end{gathered}[/tex]
Therefore, the answer is 12, option B.
