Given :
Length l=2, width w =5 and height h=6.
The volume of the pyramid is
[tex]V=\frac{lwh}{3}[/tex]
Substitute l=2, w=5, and h=6, we get
[tex]V=\frac{2\times5\times6}{3}=20units^3[/tex]
The volume of the given pyramid is 20 cubic units.
The volume is dilated by scale factor 7.
The volume of the image is
[tex]V^{\prime}=20\times7=140units^3[/tex]
The volume of the image of the pyramid is 140 cubic units.
