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Determine the momentum of a system that consists of three objects. One object, m1, has a mass of 7 kg and a velocity 23 m/s towards the north, a second object, m2, has a mass of 9 kg and a velocity 7 m/s towards the north and the third object, m3 has a mass of 5 kg and a velocity of 42 m/s towards the south .

Respuesta :

Momentum (p) = mass (m) x velocity (v)

Mometum of a system (ps) = sum of momentums

m1 = 7kg

v1 = 23 m/s (N)

m2= 9kg

v2= 7 m/s (N)

m3= 5kg

v3= 42 m/s (s) = -42m/s

Assume North is positive and South is negative

Ps = m1v1 + m2v2 + m3v3

Ps = (7 * 23 ) + (9 *7 ) + (5*-42)

Ps = 161 + 63 -210

Ps = 14 kgm/s

Answer:

Momentum of the system

14 kgm/s ,North

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