Answer
[tex]4C+6V=80[/tex]
Let's make
v = Y
C= X
[tex]4x+6y=80[/tex]
We are going to use x-intercept and y-intercept to check if the graph is correct
[tex]\begin{gathered} 4x+6y=80 \\ \text{make y the subject } \\ 6y=80-4x \\ \text{divide both sides by 6} \\ y=\frac{80-4x}{6} \end{gathered}[/tex]
The y-intercept is the point where a graph crosses the y-axis. In other words, it is the value of y when x=0
[tex]\begin{gathered} y=\frac{80-4x}{6} \\ x=0 \\ y=\frac{80-4(0)}{6} \\ \\ y=\frac{80-0}{6} \\ y=\frac{80}{6} \\ \\ y=13.33 \\ (0,13.33) \end{gathered}[/tex]
The x-intercept is the point at which the graph crosses the x-axis. At this point, the y-coordinate is zero
[tex]\begin{gathered} y=\frac{80-4x}{6} \\ \\ \text{when y=0} \\ 0=\frac{80-4x}{6} \\ cross\text{ multiply} \\ 0\times6=80-4x \\ 0=80-4x \\ 80=4x \\ \text{divide both sides by 4} \\ \frac{80}{4}=\frac{4x}{4} \\ \\ x=20 \\ (20,0) \end{gathered}[/tex]
Since, the x-intercept and y-intercept are correct the graph is true for the equation
