SOLUTION
Now, 18 is not a perfect square, because its square root is a recurring decimal
[tex]\sqrt[]{18}=4.2426406\ldots.[/tex]
18 lies between two perfect squares, which are 16 and 25
[tex]\begin{gathered} \sqrt[]{16}=4 \\ \sqrt[]{25}=5 \end{gathered}[/tex]
So the squre root of 18 will be greater than 4, but less than 5.
That is 4 is less than the square root of 18, and square root of 18 is less than 5. Which is
[tex]4<\sqrt[]{18}<5[/tex]
Option A is the correct answer
