What is the impulse if a boxer hits another boxer with 600 N of force and the glove is in contact with them for 0.2 seconds?If the impulse stayed the same but the time of contact was doubled, how much force would be exerted on them?

Impulse is calculated as force multiplied by time. So the largest impulses are created by large forces optimised for the time it takes to perform a skill.

[tex]\text{ Impulse= F}_{average}\cdot\Delta t[/tex]

so

Step 1

Let

[tex]\begin{gathered} F=600\text{ N} \\ \Delta t=t=0.2s \end{gathered}[/tex]

Step 2

replace in the expression and calculate

[tex]\begin{gathered} \text{ Impulse= F}_{average}\cdot\Delta t \\ I=600\text{ N}\cdot0.2\text{ s} \\ I=120\text{ N}\cdot s \end{gathered}[/tex]

therefore, for a)

the impulse is 120 N*s

Step 3

b)If the impulse stayed the same but the time of contact was doubled, how much force would be exerted on them?

then, let

[tex]\begin{gathered} I\text{ =(same)=120 N}\cdot s \\ t=2t_1=2\cdot0.2s=0.4s_{} \\ so\text{ , replace and solve for f} \end{gathered}[/tex]

[tex]\begin{gathered} \text{ Impulse= F}_{average}\cdot\Delta t \\ 120\text{ N}\cdot s=F\cdot0.4s \\ \text{divide both sides by 0.4 s} \\ \frac{120\text{ N}\cdot s}{0.4\text{ s}}=\frac{F\cdot0.4s}{0.4s} \\ 300\text{ N=F} \end{gathered}[/tex]

hence, the exerted force is

300 Newtons

I hope this helps you