Given:
The acceleration of the car is
[tex]a=-2.5\text{ m/s}^2[/tex]The initial velocity is
[tex]v_i=\text{ 12 m/s}[/tex]The final velocity is
[tex]v_f=\text{ 0 m/s}[/tex]Required: The time taken by the car to reach the position of rest.
Explanation:
The time can be calculated by the formula
[tex]t=\frac{v_f-v_i}{a}[/tex]On substituting the values, the time will be
[tex]\begin{gathered} t=\frac{0-12}{-2.5} \\ =4.8\text{ s} \end{gathered}[/tex]Final Answer: The time taken by the car is 4.8 s.
