Respuesta :

Let's evaluate the expression:

[tex]2x^2y^{-2}[/tex][tex]\begin{gathered} x=3 \\ y=2 \end{gathered}[/tex]

[tex]\begin{gathered} y^{-2}=\frac{1}{y^2} \\ so\colon \\ 2(3)^2\frac{1}{(2)^2}=\frac{2\times9}{4}=\frac{18}{4}=\frac{9}{2} \end{gathered}[/tex]

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