Okey, here is a list of all the posible combinations when you throw the die two times. Then I makde the sum for T and I put the probablitity of each result
Is only missing to add the probablitity for each value of T
So in most of the cases is 0.04 because:
[tex]0,04=\frac{1}{5}\cdot\frac{1}{5}[/tex]
The probability of geting any number is 1/5, then to get an exact combination you have to multiply both cases.
For 4, as there where two 4 you multiply the probability times 2, 2/5
