ANSWER
[tex]\begin{equation*} 1.90\text{ m} \end{equation*}[/tex]EXPLANATION
The maximum height of the ball occurs when the final velocity of the ball is 0 m/s.
Since the ball is thrown upwards, its acceleration is the acceleration due to gravity.
To find the maximum height reached by the ball, apply one of Newton's equations of motion:
[tex]v^2=u^2-2gs[/tex]where s = vertical distance traveled
v = final velocity
u = initial velocity
Note: -g is used instead of a since the acceleration, a, is the acceleration due to gravity in the negative(upward) direction.
Therefore, solving for s in the equation above:
[tex]\begin{gathered} 0^2=6.1^2-2*9.8*s \\ \\ 19.6s=6.1^2=37.21 \\ \\ s=\frac{37.21}{19.6} \\ \\ s=1.90\text{ m} \end{gathered}[/tex]That is the maximum height that the ball reached.
