[tex]x^2+3x-4=6[/tex]
we need to set the equation equal to 0 to factor
[tex]\begin{gathered} x^2+3x-4-6=0 \\ x^2+3x-10=0 \end{gathered}[/tex]
we can use this formula to factor
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]
where a=1,b=3 and c=-10
[tex]\begin{gathered} x=\frac{-(3)\pm\sqrt[]{(3)^2-4(1)(-10)}}{2(1)} \\ \\ x=\frac{-3\pm\sqrt[]{9+40}}{2} \\ \\ x=\frac{-3\pm\sqrt[]{49}}{2} \\ \\ x=\frac{-3\pm7}{2} \end{gathered}[/tex]
so, we have two solutions
[tex]\begin{gathered} x_1=\frac{-3+7}{2} \\ x_1=\frac{4}{2} \\ x_1=2 \end{gathered}[/tex][tex]\begin{gathered} x_2=\frac{-3-7}{2} \\ x_2=\frac{-10}{2} \\ x_2=-5 \end{gathered}[/tex]
the two solutions are {-5,2}
