customer account “numbers” for a certain company consists of 3 letters followed by 5 single digit numbers. how many different account numbers are possible if repetitions of letters and digits are allowed?

Respuesta :

Given:

The number of letters in the account number is, n(A) = 3.

The number of digits in the account number is, n(D) = 5.

The objective is to find the number of possible account numbers with repetitions.

Explanation:

The total number of letters is, N(A)=26.

The total number of digits is, N(D)=13.

The formula to find the number of possible numbers are,

[tex]P=N(A)^{n(A)}\times N(D)^{n(D)}\text{ . . . . .(1)}[/tex]

To find the number of possibilities:

Substitute the obtained values in equation (1).

[tex]\begin{gathered} P=26^3\times10^5 \\ =26\times26\times26\times10\times10\times10\times10\times10 \\ =1,757,600,000\text{ ways} \end{gathered}[/tex]

Hence, there are 1,757,600,000 ways