1/6
1) Since Tia spins spinner A once, and spins B once too, and each spinner has 4 sectors. Then we can write out:
2) The probability of getting green is the result of blue + yellow:
Note that the spinner B the yellow part is half of the spinner area. And the blue sector is equivalent to 1/6 if we trace two line on the second spinner.
[tex]\begin{gathered} P(\text{blue A) =}\frac{1}{4} \\ P(\text{yellow B) =}\frac{3}{6}=\frac{1}{2} \\ \\ P(\text{BlueA and YellowB) =}\frac{1}{4}\times\frac{1}{2}=\frac{1}{8} \\ P(\text{Yellow A and Blue B) =}\frac{1}{4}\times\frac{1}{6}=\frac{1}{24} \end{gathered}[/tex]
Since the question is one or the other, then we can add both probabilities:
[tex]P=\frac{1}{8}+\frac{1}{24}=\frac{1}{6}[/tex]
Hence, the answer is the probability of Tia getting green is 1/6
