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A solution contains a compound with a molar mass of 133.60 g/mol. How manygrams of this compound are contained if the solution has a volume of 471.4 mL and amolarity of 0.3 M?

Respuesta :

Explanation:

Given:

Molar mass of the compound = 133.60 g/mol

Volume of the solution = 471.4 mL

Molarity of the solution = 0.3 M.

The mass in grams of the compound = unknown

Note: Molarity (M) is defined as the number of moles of solute (n) divided by the volume (V) of the solution in liters, i.e

[tex]\text{Molarity }=\frac{moles}{Volume}[/tex]

1 mL = 0.001 L

So, 471.4 mL will be 0.001 x 471.4 = 0.4714 L

Therefore, the mole of the compound can be calculated as follows:

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