5 and 6
Let the two consecutive numbers be x and x+1. If the product of the numbers is 30, hence;
[tex]x(x+1)=30[/tex]Expand the expression
[tex]\begin{gathered} x^2+x=30 \\ x^2+x-30=0 \end{gathered}[/tex]Factorize
[tex]\begin{gathered} x^2+6x-5x-30=0 \\ x(x+6)-5(x+6)=0 \\ (x-5)(x+6)=0 \\ x=5\text{ }and-6 \end{gathered}[/tex]First number = 5
Second number = x+ 1 = 5+ 1
Second number = 6
Hence the two consecutive numbers whose product is 30 are 5 and 6
