we must calculate two volume and add
The volume of the figure results from finding the area of the triangle and multiplying it by the width of the figure
so
[tex]\begin{gathered} V_1=\frac{b\times h}{2}\times w \\ \\ V_1=\frac{4\times3}{2}\times9 \\ \\ V_1=\frac{12}{2}\times9 \\ \\ V_1_{}=6\times9 \\ V_1=54 \end{gathered}[/tex]
the first area is 54cubic meters
The volume of the figure results from finding the area of the square and multiplying it by the width of the figure
so
[tex]\begin{gathered} V_2=l\times l\times w \\ V_1=4\times4\times9 \\ V_1=144 \end{gathered}[/tex]
The second area is 144 cubic meters
The total volume is
[tex]144+54=198[/tex]
the total volume is 198 cubic meters
