The time taken by traveler to cover the distance is,
[tex]t=\frac{d}{v}[/tex]Substitute the known values,
[tex]\begin{gathered} t=\frac{(11000\text{ ft)}}{(84\text{ mph)(}\frac{1.46667\text{ ft/s}}{1\text{ mph}})_{}} \\ \approx89.3\text{ s} \end{gathered}[/tex]Therefore, the time taken by traveler to cover the distance is 89.3 s.
