Answer:
3.01 s
Explanation:
To calculate the time that the stick takes to reach the ground, we will use the following equation:
[tex]y=v_0t+\frac{1}{2}gt^2[/tex]
Where y is the height of the bird, v0 is the initial velocity and g is the gravity.
So, replacing v0 = 0 m/s, y = 44.5 m, and g = 9.8 m/s², we get:
[tex]\begin{gathered} 44.5=0t+\frac{1}{2}(9.8)t^2 \\ \\ 44.5=\frac{1}{2}(9.8)t^2 \\ \\ 44.5=4.9t^2 \\ \\ \frac{44.5}{4.9}=t^2 \\ \\ 9.08=t^2 \\ \\ \sqrt{9.08}=t \\ 3.01\text{ s = t} \end{gathered}[/tex]
Therefore, the stick reaches the ground after 3.01 s
