The surface area (S) of a rectangular pyramid is:
[tex]S=A+\frac{1}{2}(p*s)[/tex]
Where:
A = area of base
p = perimeter of base
s = slant height
First, let's find the area of the base:
[tex]\begin{gathered} A=12.2*12.2 \\ A=148.84ft^2 \end{gathered}[/tex]
Second, let's find the perimeter of the base:
[tex]\begin{gathered} p=12.2+12.2+12.2+12.2 \\ p=48.8ft \end{gathered}[/tex]
The slant is given and is 9.5 ft.
So, let's substitute the values and find the surface area:
[tex]\begin{gathered} S=148.84+\frac{1}{2}(48.8*9.5) \\ S=148.84+231.8 \\ S=380.64ft^2 \end{gathered}[/tex]
Answer: The surface area is 380.64 ft².
