is a problem where the Pythagorean theroem must be used
we have two sides
both sides are the legs of the triangle where the hypotenuse will be the minimum distance
so
the formula of the theorem is
[tex]h^2=a^2+b^2[/tex][tex]h^2=20^2+18^2[/tex]
where h is the distance
and a and b are t
[tex]h=8.602[/tex]
the distance is 8.02 m
you have to square both 20 and 18
[tex]h^2=400+324[/tex][tex]h^2=724[/tex][tex]h=\sqrt{724}[/tex]
h=8.04
