What is the value of x in the quadrilateral below?L3.rºM95°K(x+25)°80°N35404550

Given:
The figure shown is a trapezium.
By the property of angles of trapezium,
The sum of angles in the quadrilateral is 360 degrees.
Therefore,
[tex]\begin{gathered} 3x+(x+25)+95+80=360 \\ 4x+25=360-80-95 \\ 4x=160 \\ x=40 \end{gathered}[/tex]Hence, x= 40