3)
Given that the line passes through (-5, -5) and (-5, 3).
We have to find the slope form of the equation.
The equation passes through (x1, y1) and (x2, y2) is given by:
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
So, the required equation is:
[tex]\begin{gathered} y-(-5)=\frac{3-(-5)}{-5-(-5)}(x-(-5)) \\ y+5=\frac{8}{0}(x+5) \\ 0=8(x+5) \\ 0=x+5 \\ x=-5 \end{gathered}[/tex]
Thus, the equation of the line passes through (-5, -5) and (-5, 3) is x = -5.
