Respuesta :
Firstly we will express ppb as mass per mass:
[tex]1.0\text{ }ppb=\frac{1.0\mu g}{1kg}[/tex]By using this definition we can determine the copper in the waste water sample:
[tex]15.2ppb\text{ }Cu^{2+}=\frac{15.2\mu g\text{ }Cu^{2+}}{1kg\text{ }wastewater}[/tex]If 15.2 micrograms of copper is in 1 Kg of wastewater then in 1.23x10^3 kg of waste water we will have:
[tex]\begin{gathered} 15.2\mu g=1kg \\ x\mu g=1.23\times10^3kg \\ x=\frac{15.2\mu g\times(1.23\times10^3kg)}{1kg} \\ x=18,696\mu g \end{gathered}[/tex]Answer: 18,696 micrograms of copper would be in 1.23x10^3kg of wastewater.
