From the diagram, we get that the height we are looking for is h₂*0.914. To compute h₂ we notice that it is equal to the tangent of the depression angle times 31 yds.
Therefore:
[tex]\begin{gathered} h_2=\tan (18^{\circ})\times31\text{yds,} \\ h_2\approx10.0725\text{ yds.} \end{gathered}[/tex]
Answer: 9.21 meters.
