A bag contains 2 gold marbles, 8 silver marbles, and 29 black marbles. Someone offers to play this game: You randomly select one marble from the bag. If it is gold, you win $4. If it is silver, you win $2. If it is black, you lose $1.What is your expected value if you play this game?

Respuesta :

The bag contains:

2 gold marbles

8 silver marbles

29 black marbles

Prizes:

$4 if it's gold

$2 if it's silver

$1 if it's black

We can calculate the expected value using the following formula:

[tex]E(x)=\sum ^3_{i\mathop=1}x_i\cdot P(x_i)[/tex]

Where xi is the money you can get for each marble and P is its probability

Gold marble:

x = $4

P(x) =

[tex]P=\frac{2}{2+8+29}=\frac{2}{39}[/tex]

then, x*p(x) is

[tex]4\cdot\frac{2}{39}=\frac{8}{39}[/tex]

Silver marble:

x = $2

P(x) =

[tex]P=\frac{8}{2+8+29}=\frac{8}{39}[/tex]

then, x*p(x) is

[tex]2\cdot\frac{8}{39}=\frac{16}{39}[/tex]

Black marble:

x = $-1

P(x) =

[tex]P=\frac{29}{2+8+29}=\frac{29}{39}[/tex]

then x*p(x) is

[tex]-1\cdot\frac{29}{39}=-\frac{29}{39}[/tex]

Finally, we need to add all those x*p(x) values we got before to find the expected value, this is:

[tex]E(x)=\sum ^3_{i\mathop{=}1}x_i\cdot P(x_i)=\frac{8}{39}+\frac{16}{39}-\frac{29}{39}=-\frac{5}{39}\cong-0.1282[/tex]

Answer: your expected value if you play this game is -0.1282