It is given that the diameter of largest circle is 8 and diameter of circle is 4.
The radius of largest circle is 4.
The area of the largest circle is given by
[tex]A_1=\pir^2[/tex]
where r = 4.
Hence the area is
[tex]16\pi[/tex]
The area of the samllest circle is given by
[tex]a=\pi(2)^2[/tex]
Hence the area of smallest circle is
[tex]8\pi[/tex]
The ratio of largest to smallest circle is given by
[tex]\text{ratio}=\frac{16\pi}{8\pi}=2\colon1[/tex]
Hence the ratio is 2:1
