We have an inequality that we have to rearrange to find its solution:
[tex]\begin{gathered} \frac{x}{-2}-3\le5 \\ \frac{x}{-2}\le5+3 \\ \frac{x}{-2}\le8 \\ \frac{x}{-2}\cdot(-2)\ge8\cdot(-2) \\ x\ge-16 \end{gathered}[/tex]NOTE: when multiplying by a negative number both sides of the inequality, the order of the inequality signs has to be inverted.
