The distance that the toboggan slides before coming to a rest is given by:
[tex]d=\frac{v_0^2}{2a}[/tex]And the acceleration of the toboggan is given by:
[tex]a=\mu g[/tex]Then:
[tex]d=\frac{v_0^2}{2\mu g}=\frac{(1.8\frac{m}{s})^2}{2(0.17)(9.8\frac{m}{s^2})}=0.9724...m\approx0.97m[/tex]Therefore, the distance that the toboggan slides before coming to a rest is approximately 0.97m.
