What is the number of cycles of y = 4 sin(2011) + 2 between 0 and 2?

The given function is
[tex]y=4sin(2\theta-\frac{11\pi}{6})+2[/tex]Since the angle is 2 theta, then
That means the period is pi instead of pi/2
That means we have 2 cycles from 0 to 2pi
The correct answer is D